3(a+5)=10[a-(1-a)]

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Solution for 3(a+5)=10[a-(1-a)] equation:


Simplifying
3(a + 5) = 10[a + -1(1 + -1a)]

Reorder the terms:
3(5 + a) = 10[a + -1(1 + -1a)]
(5 * 3 + a * 3) = 10[a + -1(1 + -1a)]
(15 + 3a) = 10[a + -1(1 + -1a)]
15 + 3a = 10[a + (1 * -1 + -1a * -1)]
15 + 3a = 10[a + (-1 + 1a)]

Reorder the terms:
15 + 3a = 10[-1 + a + 1a]

Combine like terms: a + 1a = 2a
15 + 3a = 10[-1 + 2a]
15 + 3a = [-1 * 10 + 2a * 10]
15 + 3a = [-10 + 20a]

Solving
15 + 3a = -10 + 20a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-20a' to each side of the equation.
15 + 3a + -20a = -10 + 20a + -20a

Combine like terms: 3a + -20a = -17a
15 + -17a = -10 + 20a + -20a

Combine like terms: 20a + -20a = 0
15 + -17a = -10 + 0
15 + -17a = -10

Add '-15' to each side of the equation.
15 + -15 + -17a = -10 + -15

Combine like terms: 15 + -15 = 0
0 + -17a = -10 + -15
-17a = -10 + -15

Combine like terms: -10 + -15 = -25
-17a = -25

Divide each side by '-17'.
a = 1.470588235

Simplifying
a = 1.470588235

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